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X^2-4.4X+1.6=0
a = 1; b = -4.4; c = +1.6;
Δ = b2-4ac
Δ = -4.42-4·1·1.6
Δ = 12.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.4)-\sqrt{12.96}}{2*1}=\frac{4.4-\sqrt{12.96}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.4)+\sqrt{12.96}}{2*1}=\frac{4.4+\sqrt{12.96}}{2} $
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